It's total lands drawn vs non-lands drawn through the entire game.
Example:
I could have a starting hand of 3 lands and 4 non-lands. The game goes 10 turns, so I draw 10 additional cards: 4 are lands and 6 are non-lands.
Total game count: 7 lands and 10 non-lands. Which equates to 41.1% lands for the game.
Ah okay, so roughly 3.5 % of your games in duels end with you drawing 100% lands for the entire game before your opponent kills you, regardless of game length. For example, you could have drawn 20 lands in a row, or died on t4 having seen 11 lands and they would be given the same weight in your results. Am I right?
I presume you also had an opponent with real cards, right? So these results are similarly generated with real cards?
Also, could you adjust those graphs slightly, as the expected value is 26/60%, so it's really odd to group things as you have, since we can't tell where the majority of the points surrounding the expected mean actually lie... e.g. 30-40% groups numbers that are relatively far from the expected value with numbers that are nearly dead on, same issue with 40-50%. It's a real visualization problem here, and could be causing things to look more interesting than they actually are.
Tl,dr; above is important, below is also important but the graph change is more so.
The other major problem is that by drawing a random number of cards each time, the variance of each of your results is different (I don't mean Real vs. Duels, btw... I mean each X has a different variance). So we can't even calculate the expected distributions from this (even if we assume Normality, which is probably okay), we may only be able to guess at it - and our guess is not likely to be correct.
Ex: E(mean) is .433333, the simplest way to envision variance for this system however is .4333333*(1-.43333333)/n... where n here is the number of draws you took (I'm treating the system as a Bernoulli random variable where land = 1 and not land = 0, which is probably about right in case you want to look it up). 4 turn match, n =11 or 12, ten turn match, n = 17 or 18. But from what I can tell you've grouped them all together.
Regardless of how we guess at the appropriate variance (which is tricky at best) it will still have that n factor, which your data seemingly ignores.
Layman terms: you're counting average sizes of fruit, but failing to distinguish between apples, oranges, grapes, etc... while comparing the distributions of those averages as though everything were the same exact fruit.
Put in more technical terms: if the above is correct your estimator could be both biased (questionably important, but still obviously true: the result 26/60 is not possible for all n, since card numbers have discrete values*) and inconsistent (highly likely), which would make the results hard to interpret.
* the bias here stems from the fact that game length average may not be the same for Duels and Real... let's say the average real game ends on t6, while the average duels ends on t7, then the expected mean values for each will be different, based solely on the fact that the maximum likely number of expected lands seen by t6 is 6 or 46%, whereas t7 is also 6 or 43%. This could also happen if you were more often on the play or the draw, etc... the point being, your average n matters a lot, both in terms of the possible results, and in terms of the meanings of those results.
End tl,dr;
Did you keep data on number of cards drawn? Because if you did, your data is still totally useable. You should just group real vs. duels, while keeping total cards drawn fixed (I.e. N is the same for all values on both lines), and if you want to be really smart about presentation, make sure to mark the highest likelyness value on each chart. Also, I'm happy to help if you want me to.