some various things I want to address. may wind up goin' full Pheldatog on this one.
I have a list of all spy combinations, removed my name and removed all combinations that didn't include someone on the first mission.
Three people show up in more of those possible combinations than the others; its the three people from mission one.
of course they did, you removed every combination that didn't have them.
Throwing somewhat calculated numbers at you...
A team that's:
10% / 10% / 10% / 10%
Is better than one thats:
15% / 10% / 10% / 10%
And that's not including that fact that I know my alignment such that:
0% / 10% / 10% / 10%
For me, the last one is most profitable, the middle one is least profitable from a risk viewpoint.
Again, I would prefer the mission we jsut shot down, over one that has a person from the previous mission on it. I'm sure that we will need to figure out which of you isn't a spy, BUT until we know that there is a spy that ISN'T part of you three, we have a greater chance at success excluding your three from this mission.
All we know for sure is that at least one spy went on that mission.
It could've been two, and it could've even been three. Thus, until we need to figure out who is who, I say we sample a different group, and my choice is to have myself on there if at all possible.
incorrect. let's use some
fully calculated numbers.
I'm going to call mission 1 people group A and non-mission people group B. given your assumed perspective as town, there is a 2/3 chance that a person in group A is not a spy. there is a 3/5 chance that a non-you person in group B is not a spy. so let's start by putting you on the team and see what the odds of there being no spies:
1/1=1/1=100%
cool. now let's add a second person. given that 2/3(67%)>3/5(60%), the optimal person to add is from group A.
1/1*2/3=2/3=67%
there's now a 67% chance that we have no spies. since we're only concerned with the whether or not there are any spies, we're going to assume that the person we picked was not a spy, and that the spy remains out there in group A. that means we now have a 1/2(50%) chance of picking the spy there. so we take someone from group B.
1/1*2/3*3/5=2/5=40%
now at this point, if we again assume we picked the right person, we now have a 2/4(50%) chance of picking right in group B. that means that both groups have the same chance of yielding a non-spy if picked from at random. let's take from group B.
1/1*2/3*3/5*2/4=1/5=20%
and that's the best we can do at random from any given townie's perspective. but since the team can't include every townie, let's use the same process to see what a non-participant group B member's optimal result is:
ABAB=2/3*3/5*1/2*2/4=1/10=10%
you can check the other results if you want, but fortunately a greedy algorithm works fine for this problem. so from your perspective, unless you can get on the team, the best team in terms of spy avoidance has not one, but
two members of mission 1 on it. which makes sense: in order for a team with none of them to work, you have to have properly identified
every single townie outside of mission 1. (assuming only 1 spy on mission 1)
I'm not saying this is the team model we should run with. there are other factors at play here. but don't hide behind statistics if you're not going to do them right.
In the interest of being more open, I'm going to explain my hesitations now since we're closing in on the final vote time: bentz was suggested by both Zherog and razorborne. razorborne was on the first mission that failed. Now, since then, he's earned my trust, and Zherog's posts also ring Resistance for me. So I'm going with their suggestion, but if the mission fails, I'm going to be going back and seriously looking into a bentz / Zherog / razorborne triangle of Spies. Again, they have been very helpful to Resistance, so I think they're all White Hats for now, but bentz may just be their silent ringer. Maybe Mafia paranoia still lingering, but that's my gut instinct.
~SE++
I don't understand why you're trying to pin this on us. at least in my case, it was clearly a recommendation of exclusion. I wanted a team that had no mission 1 members, and didn't have alt or Zherog. that leaves a grand total of 1 possible team. exactly 1. yes, I believe bentz is town, because my theory falls apart if he isn't, but the same is equally true of you, RM, and Tiny. I never said "HEY GUYS BENTZ IS DEFINITELY TOWN". please don't try to convince people I did.
Cons of this team: Razor. Sorry, man. But On this mission, I'm not comfortable with somebody from Mission 1. The obvious reason, of course, is that at least one of those three wears a Black Hat. But there's another reason. Using Razor as way of example... if Razor wears a White Hat and this mission fails, there will be a whole lot of us assuming his hat is Black - and I think that's especially true if there is only one Fail vote. And that would be very bad, in my opinion. What we would have is at least 2 out of five (Aaargh, Mown, Squinty, Bentz, Mouse) wearing Black Hats, but sailing smooth while we had an actual good guy being shunned from future groups. To make it even worse, three of those five (Mown, Mouse, Bentz) get to form Mission Groups next, and then after the three of them make a group, if the game is still going Razor goes.
Basically, I think a failed Mission 2 that includes a player from Mission 1 muddies the water an awful lot. I certainly understand the need to sort out the data from Mission 1 and figure out who wears a Black Hat in that group. And it's very likely that a failed Mission 2 pretty much guarantees a Black Hat win regardless. But for me personally, I'd rather see the two groups be entirely different sets of people. That does make Mission 3 difficult, and it would have to include players from one or both of the first two sets. But I like to compartmentalize as much as possible
no, that's totally reasonable. I generally agree with this reasoning as well, which is part of why I'm going to vote down any team Mown puts himself on. (part. not all.) I was willing to give the team an exception because I know that having me on it reduces the chances of there being a spy on it, but I don't expect you to know that so I don't expect you to vote as if you do. I believe that from a generic town perspective, the right decision was to vote down the team. I'm not sure it was wrong to nominate it, since doing so forced a huge amount of polarizing discussion and sweet, sweet data, although given Squinty is the player I trusted most before we run out of options I'm not super happy that his proposal was rejected. but I do not think that any given player was in the wrong to reject that team.
Mown | Roaring Mouse | Bentz | seTiny Using the logic that alt and Zherog is the same alignment, it makes sense to either include or exclude both, and excluding both provides the most amount of information. However, inviting the three least vocal people is pretty troublesome, even if it generally hasn't been any indication of being a spy in previous games. And squinty isn't here for aforementioned reasons.
altimis | Zherog | Mown | Roaring Mouse Sort of the same as above, but putting them on the same team instead. Risky if they can coordinate it, or risky if my theory is wrong. Roaring Mouse is the fourth one because I know he doesn't talk a lot regardless of alignment, unlike the other two.
altimis | Zherog | Roaring Mouse | X Only if people are very opposed to having me on the team, but I've said my stance about excluding yourself before, so I don't think anyone will let me hear the end of it if I try to.
Zherog | Altimis | razorborne | squinty_eyes Try to force a team with 3 spies and look at what happens. Probably not choosing this one.
Mown | aaarrrgh | Zherog | altimis If you wanted me to put together the team that I think has the statistically most beneficial result. However, I see it as extremely unlikely to go through, which makes that irrelevant.
All things considered, I'm probably going with the first option, unless I have some revelation. I haven't actually looking at the yes/no pattern yet, so that comes first, before I settle on something. aaarrrgh accepting it is probably the most interesting part that I need to take into consideration.
I quoted this to go over analyzing the teams proposed, but by the time I got to it I realized I'd already made myself pretty clear. it's a bad idea to include yourself on a team for all the reasons Zherog outlined about it being a bad idea to include me. a team with you on it
should be rejected.
also, your recurring theory that alt and Zherog are the same alignment is, again, baseless. why must they be the same alignment, when that alignment can still be independent of the third person who voted no on that mission? why, if you're town, is your theory "they must be the same alignment but it could be either", not "they must be the same alignment as me, thus they are both town"? also why do people who vote the same way have to be the same alignment in the first place?
For that team to be all resistance it would mean that either Aaarrgh and Mown are spies OR Altimis and Zherog are spies. The first part could be true, but that would mean that aaarrgh took a risk and brought another spy on the first mission. The second part could be true but I think Altimis has been trying to scumhunt this game and has a resistance lean in my eyes.
woah.
woah woah woah woah woah.
...
...
woah.
no, you can't do that. you can't do that at all. when you're providing an argument in a game of hidden information, you can't base it on things only you know. you can't casually assume that you're town, because no one else can. you casually throw out a list of possibilities, not to argue your own position but to convince bentz, and leave off the possibility that, you know,
you're a spy? no. not ok. reeks of deception. if my Mown-Aaargh theory falls apart I have my eye on you.